CBSE Class 11 Mathematics Chapter 15 Statistics Multiple Choice Questions with Answers. MCQ Class 11 Mathematics Statistics with Answers was Prepared Based on Latest Exam Pattern. Students can solve NCERT Class 11 Mathematics Statistics MCQs with Answers to know their preparation level.
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MCQ Class 11 Mathematics Statistics with Answers - Set - 1
Question 1:
If r is the correlation coefficient, then
(a) |r| ≤ 1
(b) r ≤ 1
(c) |r| ≥ 1
(d) r ≥ 1
Correct Answer – (A)
If r is the correlation coefficient, then |r| ≤ 1
Question 2 :
If Mean = Median = Mode, then it is
(a) Symmetric distribution
(b) Asymmetric distribution
(c) Both symmetric and asymmetric distribution
(d) None of these
Correct Answer – (A)
In a symmetric distribution,
Mean = Median = Mode
Question 3 :
The median and SD of a distributed are 20 and 4 respectively. If each item is increased by 2, the new median and SD are
(a) 20, 4
(b) 22, 6
(c) 22, 4
(d) 20, 6
Correct Answer – (C)
Since each value is increased by 2, therefore the median value is also increased by
2. So, new median = 22
Again, the variance is independent of the change of origin. So it remains the same.
Question 4 :
When tested the lives (in hours) of 5 bulbs were noted as follows: 1357, 1090, 1666, 1494, 1623. The mean of the lives of 5 bulbs is
(a) 1445
(b) 1446
(c) 1447
(d) 1448
Correct Answer – (B)
Given, lives (in hours) of 5 bulbs were noted as follows: 1357, 1090, 1666, 1494, 1623
Now, mean = (1357 + 1090 + 1666 + 1494 + 1623)/5
= 7230/5
= 1446
Question 5 :
The algebraic sum of the deviation of 20 observations measured from 30 is 2. So, the mean of observations is
(a) 30.0
(b) 30.1
(c) 30.2
(d) 30.3
Correct Answer – (B)
Given, algebraic sum of of the deviation of 20 observations measured from 30 is 2
⇒ ∑(xi – 30) = 2 {1 ≤ i ≤ 20}
⇒ ∑xi – 30 × 20 = 2
⇒ (∑xi)/20 – (30 × 20)/20 = 2/20
⇒ (∑xi)/20 – 30 = 0.1
⇒ Mean – 30 = 0.1
⇒ Mean = 30 + 0.1
⇒ Mean = 30.1
MCQ Class 11 Mathematics Statistics with Answers
Question 6 :
If the difference of mode and median of a data is 24, then the difference of median and mean is
(a) 12
(b) 24
(c) 8
(d) 36
Correct Answer – (A)
Given the difference of mode and median of a data is 24
⇒ Mode – Median = 24
⇒ Mode = Median + 24
Now, Mode = 3×Median – 2×Mean
⇒ Median + 24 = 3×Median – 2×Mean
⇒ 24 = 3×Median – 2×Mean – Median
⇒ 24 = 2×Median – 2×Mean
⇒ Median – Mean = 24/2
⇒ Median – Mean = 12
Question 7 :
Range of the data 4, 7, 8, 9, 10, 12, 13 and 17 is
(a) 4
(b) 17
(c) 13
(d) 21
Correct Answer – (C)
Range = Maximum value – Minimum Value
= 17 – 4
= 13
Question 8 :
If mode of a series exceeds its mean by 12, then mode exceeds the median by
(a) 4
(b) 8
(c) 6
(d) 12
Correct Answer – (B)
Given, Mode = Mean + 12
⇒ Mode – 12 = Mean
Now, Mode = 3×Median – 2×Mean
⇒ Mode = 3×Median – 2(Mode – 12)
⇒ Mode = 3×Median – 2×Mode + 24
⇒ Mode + 2×Mode = 3×Median + 24
⇒ 3×Mode = 3×Median = 24
⇒ Mode = Median + 8
So, mode exceeds the median by 8
Question 9 :
The coefficient of variation is computed by
(a) S.D/.Mean×100
(b) S.D./Mean
(c) Mean./S.D×100
(d) Mean/S.D.
Correct Answer – (B)
The coefficient of variation = S.D./Mean
Question 10 :
The sum of 10 items is 12 and the sum of their squares is 18. The standard deviation is
(a) 1/5
(b) 2/5
(c) 3/5
(d) 4/5
Correct Answer – (C)
Given, ∑x = 12 and ∑x² = 18
Now, variance = ∑x²/n – (∑x/n)²
⇒ variance = 18/10 – (12/10)²
⇒ variance = 9/5 – (6/5)²
⇒ variance = 9/5 – 36/25
⇒ variance = (9 × 5 – 36)/25
⇒ variance = (45 – 36)/25
⇒ variance = 9/25
⇒ Standard deviation = √(9/25)
⇒ Standard deviation = 3/5
- NCERT Solutions Class 11 Mathematics Statistics with Answers : Exercise 15.1
- NCERT Solutions Class 11 Mathematics Statistics with Answers : Exercise 15.2
- NCERT Solutions Class 11 Mathematics Statistics with Answers : Exercise 15.3
- NCERT Solutions Class 11 Mathematics Statistics with Answers : Exercise 15 Misc
- NCERT Solutions Class 11 Mathematics Textbook download
