CBSE Class 10 Mathematics Chapter 13 Surface Areas and Volumes Multiple Choice Questions with Answers. MCQ Class 10 Maths Surface Areas and Volumes with Answers was Prepared Based on Latest Exam Pattern. Students can solve NCERT Class 10 Mathematics Surface Areas and Volumes MCQs with Answers to know their preparation level.
Multiple Choice Questions - Set - 6
Question 1:
(a) 6m, 450m²
(b) 5m, 560m²
(c) 2m, 780m²
(d) 5.88m, 434m²
Correct Answer – (A)
Question 2 :
(a) 5.6721 l
(b) 4.0218 l
(c) 3.8925 l
(d) 4.97 l
Correct Answer – (B)
Question 3 :
(a) 1 : 2
(b) 2 : 1
(c) 1 : 4
(d) 4 : 1
Correct Answer – (C)
Question 4 :
(a) increase by 1
(b) the same
(c) double
(d) triple
Correct Answer – (B)
Question 5 :
Two identical solid hemispheres of equal base radius r cm are stuck together along their bases. The total surface area of the combination is
(a) 6πr2
(b) 5πr2
(c) 4πr2
(d) 3πr2
Correct Answer – (C)
When two hemispheres are joined together along their bases, a sphere of the same base radius is formed.
Curved Surface Area of a sphere = 4πr2
Question 6 :
A well with 10 m inside diameter is dug 14m deep. Earth taken out of it is spread all around it to make an embankment of height 4(2/3) Find the width of the embankment.
(a) 5 m
(b) 4 m
(c) 4.3 m
(d) 6 m
Correct Answer – (A)
Question 7 :
Two right circular cones of equal curved surface areas have slant heights in the ratio of 3 : 5. Find the ratio of their radii.
(a) 4 : 1
(b) 3 : 5
(c) 5 : 3
(d) 4 : 5
Correct Answer – (C)
Question 8 :
If a right circular cone hs radius 4 cm and slant height 5 cm then what is its volume?
(a) 16 π cm3
(b) 14 π cm3
(c) 12 π cm3
(d) 18 π cm3
Correct Answer – (A)
Question 9 :
What is the total surface area of a hemisphere of radius r?
(a) 4πr2
(b) πr2
(c) 2πr2
(d) 3πr2
Correct Answer – (D)
Question 10 :
The number of shots each having diameter 3 cm can be made from a cuboidal lead solid of dimensions 9 cm × 11 cm × 12 cm is approximately equal to
(a) 84
(b) 90
(c) 92
(d) 80
Correct Answer – (A)
Volume of cuboidal lead solid = 9 cm × 11 cm × 12 cm = 1188 cm3
Radius of lead shot = 3/2 cm = 1.5 cm
Volume of each shot = (4/3)πr3
= (4/3) × (22/7) × 1.5 × 1.5 × 1.5
= 14.143 cm3
Number of lead shots can be made = 1188/14.143 = 84 (approx.)
- NCERT Solutions Class 10 Mathematics Surface Areas and Volumes : Exercise 13.1
- NCERT Solutions Class 10 Mathematics Surface Areas and Volumes : Exercise 13.2
- NCERT Solutions Class 10 Mathematics Surface Areas and Volumes : Exercise 13.3
- NCERT Solutions Class 10 Mathematics Surface Areas and Volumes : Exercise 13.4
- NCERT Solutions Class 10 Mathematics Surface Areas and Volumes : Exercise 13.5
