Chemical bonding and molecular structure-1

MCQ Questions Class 11 Chemistry Chemical Bonding and Molecular Structure with Answers

CBSE Class 11 Chemistry Chapter 4 Chemical Bonding and Molecular Structure Multiple Choice Questions with Answers. MCQ Questions Class 11 Chemistry Chemical Bonding and Molecular Structure with Answers was Prepared Based on Latest Exam Pattern. Students can solve NCERT Class 11 Chemistry Chemical Bonding and Molecular Structure MCQs with Answers to know their preparation level.

Students who are searching for NCERT MCQ Questions for Class 11 Chemistry Chemical Bonding and Molecular Structure with Answers are compiled here to get good practice on all fundamentals. Know your preparation level on MCQ Questions for Class 11 Chemistry with Answers. You can also verify your answers from our provided MCQ Class 11 Chemistry Chemical Bonding and Molecular Structure with Answers. So, ace up your preparation with MCQ of Chapter 4 Chemistry Objective Questions.

MCQ Questions Class 11 Chemistry Chemical Bonding and Molecular Structure with Answers - Set - 1

Question 1: 

An atom of an element A has three electrons in its outermost orbit and that of B has six electrons in its outermost orbit. The formula of the compound between these two will be
(a) A3B6
(b) A2B3
(c) A3B2
(d) A2B

Correct Answer – (B)
Explanation:
A has 3 electrons in outermost orbit and B has 6 electrons in its outermost orbits. So A can give three electrons to complete its octet and B needs 2 electrons to complete its octet. So 2 atoms of A will release 6 electrons and 3 atoms of B will need six electrons to complete their octet
So, the formula will be A2B3

Question 2 : 

The value of n in the molecular formula BenAl2Si6O18 is
(a) 3
(b) 5
(c) 7
(d) 9

Correct Answer – (A)
Explanation:
BenAl2Si6O18
The oxidation states of each element
Be = +2
Al = +3
Si = +4
O = -2
(2n) + (3 × 2) + (4 + 6) + (−2 × 18) = 0
or 2n + 30 − 36 = 0
or 2n = 6
or n = 3

Question 3 : 

Among the following the maximum covalent character is shown by the compound
(a) MgCl2
(b) FeCl2
(c) SnCl2
(d) AlCl3

Correct Answer – (D)

Explanation:
We know that, extent of polarisation ∝ covalent character in ionic bond. Fajans rule states that the polarising power of cation increases, with increase in magnitude of positive charge on the cation Therefore, polarising power ∝ charge of cation.

The polarising power of cation increases with the decrease in the size of a cation. Therefore, polarising (power) ∝ (1)/ (size of cation)
Here the AlCl3 is satisfying the above two conditions i.e., Al is in +3 oxidation state and also has small size. So it has more covalent character.

Question 4 : 

Which one of the following does not have sp² hybridised carbon?
(a) Acetone
(b) Acetic acid
(c) Acetonitrile
(d) Acetamide

Correct Answer – (C)

Question 5 : 

The number of nodal planes present in s × s antibonding orbitals is
(a) 1
(b) 2
(c) 0
(d) 3

Correct Answer – (A)
In an antibonding molecular orbital, most of the electron density is located away from the space between the nuclei, as a result of which there is a nodal plane (i.e, a plane at which the electron density is zero) between the nuclei

MCQ Questions Class 11 Chemistry Chemical Bonding and Molecular Structure with Answers

Question 6 : 

Which of the following types of hybridisation leads to three dimensional geometry of bonds around the carbon atom?
(a) sp
(b) sp²
(c) sp³
(d) None of these

Correct Answer – (B)
Explanation:
sp² hybrid structures have trigonal planar geometry, which is two dimensional

Question 7 : 

Among the following mixtures, dipole-dipole as the major interaction, is present in
(a) benzene and ethanol
(b) acetonitrile and acetone
(c) KCl and water
(d) benzene and carbon tetrachloride

Correct Answer – (B)
Explanation:
Dipole-dipole interactions occur among the polar molecules. Polar molecules have permanent dipoles. The positive pole of one molecule is thus attracted by the negative pole of the other molecule. The magnitude of dipole-dipole forces in different polar molecules is predicted on the basis of the polarity of the molecules, which in turn depends upon the electro negativities of the atoms present in the molecule and the geometry of the molecule (in case of polyatomic molecules, containing more than two atoms in a molecule).

Question 8 : 

Which of the following will have the lowest boiling point?
(a) 2-MethylButane
(b) 2-MethylPropane
(c) 2,2-Dimethylpropane
(d) n-Pentane

Correct Answer – (D)
Explanation:
Boiling point increases with increase in molecular mass. For the compounds with the same molecular mass, boiling point decreases with an increase in branching.
The molecular mass of 2-Methylbutane: 72 g mol-1
The molecular mass of 2-Methylpropane: 58 g mol-1
The molecular mass of 2, 2-Dimethylpropane: 72 g mol-1
The molecular mass of 2-Methylbutane: 72 g mol-1
2-Methylpropane has the lowest molecular mass among all of the given compounds.
Thus, 2-Methylpropane has the lowest boiling point among the given options.

Question 9 : 

The hybrid state of sulphur in SO2 molecule is :
(a) sp²
(b) sp³
(c) sp
(d) sp³d

Correct Answer – (A)
Explanation:
The hybridisation of sulphur in SO2 is sp². Sulphur atom has one lone pair of electrons and two bonding domains. Bond angle is <120° and molecular geometry is V-shape, bent or angular

Question 10 : 

The bond length between hybridised carbon atom and other carbon atom is minimum in
(a) Propane
(b) Butane
(c) Propene
(d) Propyne

Correct Answer – (D)
Explanation:
The C – C bond length = 1.54 Å, C = C bond length = 1.34 Å and C ≡ C bond length = 1.20 Å.
Since propyne has a triple bond, therefore it has minimum bond length

MCQ Questions Class 11 Chemistry Chemical Bonding and Molecular Structure with Answers

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