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MCQ Questions Class 11 Chemistry Classification of Elements and Periodicity in Properties with Answers

CBSE Class 11 Chemistry Chapter 3 Classification of Elements and Periodicity in Properties Multiple Choice Questions with Answers. MCQ Questions Class 11 Chemistry Classification of Elements and Periodicity in Properties with Answers was Prepared Based on Latest Exam Pattern. Students can solve NCERT Class 11 Chemistry Classification of Elements and Periodicity in Properties MCQs with Answers to know their preparation level.

Students who are searching for NCERT MCQ Questions for Class 11 Chemistry Classification of Elements and Periodicity in Properties with Answers are compiled here to get good practice on all fundamentals. Know your preparation level on MCQ Questions for Class 11 Chemistry with Answers. You can also verify your answers from our provided MCQ Class 11 Chemistry Classification of Elements and Periodicity in Properties with Answers. So, ace up your preparation with MCQ of Chapter 3 Chemistry Objective Questions.

MCQ Questions Class 11 Chemistry Classification of Elements and Periodicity in Properties with Answers - Set - 2

Question 1: 

Increasing order of electro negativity is
(a) Bi < P < S < Cl
(b) P < Bi < S < Cl
(c) S < Bi < P < Cl
(d) Cl < S < Bi < P

Correct Answer – (A)
Explanation:
Increasing order of electro negativity is Bi < P < S < Cl

Question 2 : 

On the Paulings electro negativity scale the element next to F is
(a) N
(b) Cl
(c) O
(d) Ne.

Correct Answer – (C)
Explanation:
Pauling explained electro negativity as the power of an atom in a molecule to attract electrons towards it. When we analyse the trend in periodic table, we can see that the degree of electro negativity decreases while going down the groups, while it increases across the periods. In the case of a covalent bond, based on the bond energies, Pauling calculated the differences in electro negativity between atoms in the bond and assigned a value of 4 to fluorine, which is the most electro negative element, and others were calculated with respect to that value. Hence, on paulings scale, the element next to fluorine is Oxygen.

Question 3 : 

The electronic configuration of halogen is
(a) ns² np6
(b) ns² np3
(c) ns² np5
(d) ns²

Correct Answer – (C)
Explanation:
Halogens has 7 electrons in his valance shell (ns²np5)

Question 4 : 

The reduction in atomic size with increase in atomic number is a characteristic of elements of-
(a) d−block
(b) f−block
(c) Radioactive series
(d) High atomic masses

Correct Answer – (B)
Explanation:
The reduction in atomic size with increase in atomic number is a characteristic of elements of f- block. It is known as lanthanoid contraction and actinoid contraction. This is due to poor shielding of electrons present in f subshell

Question 5 : 

In the modern periodic table , the period indicates the value of:
(a) Atomic Number
(b) Atomic Mass
(c) Principal Quantum Number
(d) Azimuthal Quantum Number

Correct Answer – (C)
Explanation:
The periodic table is a tabular arrangement of the chemical elements, organized on the basis of their atomic number (number of protons in the nucleus), electron configurations, and recurring chemical properties.
The value of the principal quantum number (n) for the outermost shell or the valence shell indicates a period in the Modern periodic table

MCQ Questions Class 11 Chemistry Classification of Elements and Periodicity in Properties with Answers

Question 6 : 

The element californium belongs to a family of :
(a) Alkali metal family
(b) Actinide series
(c) Alkaline earth family
(d) Lanthanide series

Correct Answer – (B)
Explanation:
Atomic number of californium is 98 and its electronic configuration is
Rn86 7s² 5f10
so it is a f-block element and as it is in 7th period, it is a part of actinide series

Question 7 : 

Which of the following forms the most stable gaseous negative ion?
(a) F
(b) Cl
(c) Br
(d) I

Correct Answer – (B)
Explanation:
The element which forms the most stable gaseous negative ion is fluorine

Question 8 : 

The number of elements in the 5th period of the periodic table is
(a) 3
(b) 9
(c) 8
(d) 18

Correct Answer – (D)
Explanation:
While filling 5th shell according to Aufbau principle 5s, 5p, 4d filled so 2 + 6 + 10 = 18 electrons or elements are present in 5th shell. Further we start filling the 4d orbital which can take 10 electrons. So in the 4th principal quantum energy states, we can fill 18 electrons. Thus 5th period has 18 elements

Question 9 : 

The electronic configuration of an element is 1s², 2s² 2p6, 3s² 3p³. What is the atomic number of the element which is just below the above element in the periodic table
(a) 31
(b) 34
(c) 33
(d) 49

Correct Answer – (C)
Explanation:
33−1s²2s²2p63s²3p63d104s²4p³

Question 10 : 

Arrange S, O and Se in ascending order of electron affinity
(a) Se < S < O
(b) Se < O < S
(c) S < O < Se
(d) S < Se < O

Correct Answer – (A)
Explanation:
Correct order of electron affinity is Se < S < O. In a group electron affinity decreases with increase in atomic number.

MCQ Questions Class 11 Chemistry Classification of Elements and Periodicity in Properties with Answers

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