CBSE Class 11 Chemistry Chapter 7 Equilibrium Multiple Choice Questions with Answers. MCQ Questions Class 11 Chemistry Equilibrium with Answers was Prepared Based on Latest Exam Pattern. Students can solve NCERT Class 11 Chemistry Equilibrium MCQs with Answers to know their preparation level.
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MCQ Questions Class 11 Chemistry Equilibrium with Answers - Set - 1
Question 1:
In a reversible chemical reaction at equilibrium, if the concentration of any one of the reactants is doubled, then the equilibrium constant will
(a) Also be Doubled
(b) Be Halved
(c) Remain the Same
(d) Become One-Fourth
Correct Answer – (C)
Explanation:
Equilibrium constants are not changed if you change the concentrations of things present in the equilibrium. The only thing that changes an equilibrium constant is a change of temperature.
The position of equilibrium is changed if you change the concentration of something present in the mixture. According to Le Chateliers Principle, the position of equilibrium moves in such a way as to tend to undo the change that you have made.
According to Le Chateliers Principle, if you increase the concentration of Reactant, for example, the position of equilibrium will move to the right to decrease the concentration of reactant again.
Question 2 :
When equal volumes of 0.1 M NaOH and 0.01 M HCl are mixed, the hydroxide ion concentration is
(a) 7.0
(b) 1.04
(c) 12.65
(d) 2.0
Correct Answer – (C)
When equal volumes of 0.1 M NaOH and 0.01 M HCl are mixed, the hydroxide ion concentration is
(0.1 – 0.01)/(2)
= 0.045 M
The pOH of the solution is pOH = −log [OH–]
= −log 0.045
= 1.35
The pH of the solution is pH = 14 − pOH
= 14 − 1.35
= 12.65
Question 3 :
The pH of a 10-10 M NaOH solution is nearest to
(a) 10
(b) 7
(c) 4
(d) -10
Correct Answer – (C)
pOH= −log [OH–]
= −log 10-10
= 10 log 10
= 10pH + pOH
= 14pH
= 14−pOH
= 14−10
= 4
Question 4 :
What is the pH of a 0.10 M solution of barium hydroxide, Ba (OH)2?
(a) 11.31
(b) 11.7
(c) 13.30
(d) None of these
Correct Answer – (C)
pH = 13.30
Barium hydroxide is a strong base for both stages of dissociation:
Ba (OH)2(s) → Ba2+ + 2OH–
So the solution will have 0.20 M hydroxide ions. Now use the auto dissociation product for water:
[H+][OH–] = 1.0 × 10-14M
[OH–] = 2.0 × 10-1M
[H+] = 5.0 × 10-14M
And then pH = −log10 ([H+] = 5.0 × 10-14)
= 13.30.
Question 5 :
A physician wishes to prepare a buffer solution at pH = 3.85 that efficiently resists changes in pH yet contains only small concentration of the buffering agents. Which of the following weak acids together with its sodium salt would be best to use?
(a) 2, 5-Dihydroxy benzoic acid (pKa = 2.97)
(b) Acetoacetic acid (pKa = 3.58)
(c) m-Chlorobenzoic acid (pKa = 3.98)
(d) p-Chlorocinnamic acid (pKa = 4.41)
Correct Answer – (B)
MCQ Questions Class 11 Chemistry Equilibrium with Answers
Question 6 :
Concentration of the Ag+ ions in a saturated solution of Ag2C2O4 is 2.2 x 10-4 mol L-1. Solubility product of Ag2C2O42 is
(a) 2.66 × 10-12
(b) 4.5 × 10-11
(c) 5.3 × 10-12
(d) 2.42 × 10-8
Correct Answer – (C)
[Ag+] = 2.2 × 10-4 mol L-1
[C2O42-] = 0.5[Ag+] = 0.5 × 2.2 × 10-4 mol L-1 = 1.1 × 10-4 mol L-1
Ksp =[Ag+]² [C2O42-]Ksp
= (2.2 × 10-4 mol L-1)² × 1.1 × 10-4 mol L-1
Ksp = 5.3 × 10-12
Question 7 :
A weak acid HX has the dissociation constant 1 × 10-5 M. It forms a salt NaX on reaction with alkali. The degree of hydrolysis of 0.1 M solution of NaX is
(a) 0.0001%
(b) 0.01%
(c) 0.1%
(d) 0.15%
Correct Answer – (B)
NaX: Salt of weak acid, strong base.
⇒ α = (√Kh/c)
= √ (Kw)/ (KaC)
= (10-14)/(10-5×0.1)
= 10-4
⇒ % hydrolysis = 0.01%
Question 8 :
Which of the following oxides is not expected to react with sodium hydroxide?
(a) CaO
(b) SiO2
(c) BeO
(d) B2O3
Correct Answer – (A)
CaO being a basic oxide does not react with NaOH, however SiO2 (acidic oxide), BeO (amphoteric oxide) and Br2O3 (acidic oxide) react with NaOH
Question 9 :
Which of the following aqueous solutions will have highest pH?
(a) NaCl
(b) CH3COONa
(c) Na2CO3
(d) NH4Cl
Correct Answer – (C)
NaCl is salt of strong acid and strong base so it has pH of about 7.
NH4Cl is salt of strong acid and weak base so it has pH is much less than 7.
CH3COONH4 is salt of weak acid and weak base so it has pH of about 7.
Na2CO3 is salt of weak acid and strong base so it has pH is much greater than 7
Question 10 :
The solubility of Ca3(PO4)2 in water is y mol/L. Its solubility product is:
(a) 6y²
(b) 36 y4
(c) 64 y5
(d) 108 y5
Correct Answer – (D)
- NCERT Solutions Class 11 Chemistry Chapter 1 : Some Basic Concepts of Chemistry
- NCERT Solutions Class 11 Chemistry Chapter 2 : Structure Of The Atom
- NCERT Solutions Class 11 Chemistry Chapter 3 : Classification of Elements and Periodicity in Properties
- NCERT Solutions Class 11 Chemistry Chapter 4 : Chemical Bonding and Molecular Structure
- NCERT Solutions Class 11 Chemistry Chapter 5 : States of Matter
- NCERT Solutions Class 11 Chemistry Chapter 6 : Thermodynamics
- NCERT Solutions Class 11 Chemistry Chapter 7 : Equilibrium
- NCERT Solutions Class 11 Chemistry Chapter 8 : Redox Reactions
- NCERT Solutions Class 11 Chemistry Chapter 9 : Hydrogen
- NCERT Solutions Class 11 Chemistry Chapter 10 : The s-Block Elements
- NCERT Solutions Class 11 Chemistry Chapter 11 : The p-Block Elements
- NCERT Solutions Class 11 Chemistry Chapter 12 : Organic Chemistry: Some Basic Principles and Techniques
- NCERT Solutions Class 11 Chemistry Chapter 13 : Hydrocarbons
- NCERT Solutions Class 11 Chemistry Chapter 14 : Environmental Chemistry
