CBSE Class 11 Chemistry Chapter 7 Equilibrium Multiple Choice Questions with Answers. MCQ Questions Class 11 Chemistry Equilibrium with Answers was Prepared Based on Latest Exam Pattern. Students can solve NCERT Class 11 Chemistry Equilibrium MCQs with Answers to know their preparation level.
Students who are searching for NCERT MCQ Questions for Class 11 Chemistry Equilibrium with Answers are compiled here to get good practice on all fundamentals. Know your preparation level on MCQ Questions for Class 11 Chemistry with Answers. You can also verify your answers from our provided MCQ Class 11 Chemistry Equilibrium with Answers. So, ace up your preparation with MCQ of Chapter 7 Chemistry Objective Questions.
MCQ Questions Class 11 Chemistry Equilibrium with Answers - Set - 2
Question 1:
Amines behave as
(a) Lewis Acids
(b) Lewis Base
(c) Aprotic Acid
(d) Neutral Compound
Correct Answer – (B)
R−NH2 (Amines) behaves as a Lewis base because it is capable of donating a lone pair of electron
Question 2 :
Which of the following mixtures in aqueous solution of equimolar concentration acts as a buffer solution?
(a) HNO3 and NaOH
(b) H2SO4 and KOH
(c) NH4OH(excess) + HCl
(d) CH3COOH and NaOH(excess)
Correct Answer – (C)
A mixture of ammonium hydroxide and HCl react to form ammonium chloride. This also contains unreacted ammonium hydroxide.
NH4 OH + HCl → NH4Cl + H2O
Thus, the resulting mixture of (NH4OH+NH4Cl) is a basic buffer solution. It contains a mixture of weak base ammonium hydroxide and its salt (ammonium chloride) with strong acid (HCl).
It is used in a qualitative analysis of group III radicals.
A mixture of HNO3 and NaOH is a mixture of strong acid and strong base similarly a mixture of
H2SO4 and KOH is also a mixture of strong acid and strong base, thus they do not form buffer solution.
Similarly, in option 4 mixture will form a strong base and salt of strong base weak acid hence it will not form a buffer solution
Question 3 :
Solubility of M2S salt is 3.5 × 10-6 then find out solubility product.
(a) 1.7 × 10-6
(b) 1.7 × 10-16
(c) 1.7 × 10-18
(d) 1.7 × 10-12
Correct Answer – (B)
Let ”s“ be the solubility of salt M2S which undergoes dissociation as follows :-
M2S ⇌ 2M+ +S-2
Initial concentration 1 0 0
Concentration at equilibrium 1-s 2s s
Hence, the solubility product (Ksp) = (s) × (2s)²
Therefore, Ksp = 4 × s³
Or Ksp = 4× (3.5×10-6)³
⇒ Ksp
= 1.7 × 10-16
Question 4 :
A certain buffer solution contains equal concentration of X– and HX. The ka for HX is 10-8. The pH of the buffer is
(a) 3
(b) 8
(c) 11
(d) 14
Correct Answer – (B)
ka kb = kw
kb = 10-8
ka × 10-8 = 10-14
ka = 10-6 = [H+]
pH = −log [H+]
pH = −log 10-6
= 6pH + pOH
= 14 pOH
= 14−6
= 8
Question 5 :
Concentration of the Ag-4 ions in a saturated solution of Ag2C2O4 is 2.2 × (a) 10-4 mol L-1. Solubility product of Ag2C2O4 is
(b) 2.66 × 10-12
(c) 4.5 × 10-11
(d) 5.3 × 10-12
2.42 × 10-8
Correct Answer – (C)
[Ag+] = 2.2 × 10-4 mol L-1
[C2O42-] = 0.5[Ag+] = 0.5 × 2.2 × 10-4 mol L-1 =1.1×10-4 mol L-1
Ksp = [Ag+]² [C2O42-] Ksp
= (2.2 × 10-4 mol L-1)² × 1.1 × 10-4 mol L-1
Ksp = 5.3 × 10-12
MCQ Questions Class 11 Chemistry Equilibrium with Answers
Question 6 :
Which of the following aqueous solutions will have highest pH?
(a) NaCl
(b) CH3COONa
(c) Na2CO3
(d) NH4Cl
Correct Answer – (C)
NaCl is salt of strong acid and strong base so it has pH of about 7.
NH4Cl is salt of strong acid and weak base so it has pH is much less than 7.
CH3COONH4 is salt of weak acid and weak base so it has pH of about 7.
Na2CO3 is salt of weak acid and strong base so it has pH is much greater than 7
Question 7 :
Among the following hydroxides, the one which has the lowest value of Ksp at ordinary temperature (about 25°C ) is
(a) Mg (OH)2
(b) Ca(OH)2
(c) Ba(OH)2
(d) Be(OH)2
Correct Answer – (D)
Explanation:
Be(OH)2 has the lowest value of Ksp at ordinary temperature because Be2+ ion is smaller than the other metal ions in the group, which results in a tighter bond with the 0H– ions, thus much lower solubility.
The solubility of a hydroxide of group 2 elements increases down the group because as you go down the group size of metal increases thereby increasing the bond length and decreasing bond energy
Question 8 :
What is the pH of a 0.10 M solution of barium hydroxide, Ba (OH)2?
(a) 11.31
(b) 11.7
(c) 13.30
(d) None of these
Correct Answer – (C)
pH =13.30
Barium hydroxide is a strong base for both stages of dissociation:
Ba (OH)2(s) → Ba2+ + 2OH–
So the solution will have 0.20 M hydroxide ions. Now use the auto dissociation product for water:
[H+][OH–] = 1.0×10-14M
[OH–] = 2.0 × 10-1M
[H+] = 5.0 × 10-14M
And then pH = −log10 ([H+] = 5.0 × 10-14)
= 13.30
Question 9 :
Among the following the weakest Bronsted base is
(a) F–
(b) Cl–
(c) Br–
(d) I–
Correct Answer – (D)
According to this theory, an acid is a proton donor and a base is a proton acceptor. Every strong Bronsted acid has a weak conjugate base and every strong base has a weak conjugate acid. The acidity increases in halogen group atoms,
HF < HCl < HBr < HI.
So, HI is highly acidic and their conjugate bases decrease in order F– > Cl– > Br– > I–.
Question 10 :
When a neutral atom undergoes oxidation, the atoms oxidation state
(a) Decreases as it gains electrons
(b) Decreases as it loses electrons
(c) Increases as it gains electrons
(d) Increases as it loses electrons
Correct Answer – (D)
The acronym “OILRIG” can be used to remember this: Oxidation is Losing electrons, Reduction is Gaining electrons. Therefore, when an atom undergoes oxidation, it loses electrons. This makes its net charge more positive, so its oxidation state increases
- NCERT Solutions Class 11 Chemistry Chapter 1 : Some Basic Concepts of Chemistry
- NCERT Solutions Class 11 Chemistry Chapter 2 : Structure Of The Atom
- NCERT Solutions Class 11 Chemistry Chapter 3 : Classification of Elements and Periodicity in Properties
- NCERT Solutions Class 11 Chemistry Chapter 4 : Chemical Bonding and Molecular Structure
- NCERT Solutions Class 11 Chemistry Chapter 5 : States of Matter
- NCERT Solutions Class 11 Chemistry Chapter 6 : Thermodynamics
- NCERT Solutions Class 11 Chemistry Chapter 7 : Equilibrium
- NCERT Solutions Class 11 Chemistry Chapter 8 : Redox Reactions
- NCERT Solutions Class 11 Chemistry Chapter 9 : Hydrogen
- NCERT Solutions Class 11 Chemistry Chapter 10 : The s-Block Elements
- NCERT Solutions Class 11 Chemistry Chapter 11 : The p-Block Elements
- NCERT Solutions Class 11 Chemistry Chapter 12 : Organic Chemistry: Some Basic Principles and Techniques
- NCERT Solutions Class 11 Chemistry Chapter 13 : Hydrocarbons
- NCERT Solutions Class 11 Chemistry Chapter 14 : Environmental Chemistry
