CBSE Class 10 Mathematics Chapter 12 Areas Related to Circles Multiple Choice Questions with Answers. MCQ Class 10 Maths Areas Related to Circles with Answers was Prepared Based on Latest Exam Pattern. Students can solve NCERT Class 10 Mathematics Areas Related to Circles MCQs with Answers to know their preparation level.
Multiple Choice Questions - Set - 4
Question 1:
A horse is tied to a peg at one corner of a square shaped grass field of side 15 m by means of a 7 m long rope. The area of that part of the field in which the horse can graze, is
(a) 77 cm²
(a) 77/2 cm²
(a) 154 cm²
(a) 77/4 cm²
Correct Answer – (B)
Question 2 :
The area of a quadrant of a circle whose circumference is 22 cm, is
(a) 11/8 cm2
(b) 77/2 cm2
(c) 77/4 cm2
(d) 77/8 cm2
Correct Answer – (D)
Question 3 :
The area of the circle is 154 cm2. The radius of the circle is
(a) 7 cm
(b) 14 cm
(c) 3.5 cm
d) 17.5 cm
Correct Answer – (D)
Reason: Area of circle = 154 cm²
⇒ πr² = 154 cm2
22/7 × r² = 154
⇒ r² = 154 × 7/22
⇒ r² = 7 × 7 = 49
∴ r = √49 = 7
Question 4 :
Area of a sector of central angle 120° of a circle is 3π cm2. Then the length of the corresponding arc of this sector is:
(A) 5.8cm
(B) 6.1cm
(C) 6.3cm
(D) 6.8cm
Correct Answer – (C)
Question 5 :
A cow is tied with a rope of length 14 m at the corner of a rectangular field of dimensions 20m × 16m, then the area of the field in which the cow can graze is:
(A) 154 m2
(B) 156 m2
(C) 158 m2
(D) 160 m2
Correct Answer – (A)
Area of the field in which cow can graze= Area of a sector AFEG
= (θ/360) X πr2
= (90/360) X π (14)2
= (1/4) X (22/7) X 196
= 154 m2
Question 6 :
If θ is the angle in degrees of a sector of a circle of radius V, then area of the sector is
(a) πr2θ/180
(b) πr2θ/360
(c) 2πrθ/180
(d) 2πrθ/360
Correct Answer – (B)
Question 7 :
If angle of sector is 60°, radius is 3.5 cm then length of the arc is
(a) 3 cm
(b) 3.5 cm
(c) 3.66 cm
(d) 3.8 cm
Correct Answer – (C)
Question 8 :
A round table cover has six equal designs as shown in the figure. If the radius of thecover is 28 cm, then the cost of making the design at the rate of Rs. 0.35 per cm2 is:
(A) Rs.146.50
(B) Rs.148.75
(C) Rs.152.25
(D) Rs.154.75
Correct Answer – (B)
The area of the hexagon will be equal to six equilateral triangles with each side equal to the radius of circle.
Area of given hexagon = Area of 6 equilateral triangles.
= 6 X (√3/4) X (side)2
= 6 X (√3/4) X (28)2
= 1999.2 cm2 (Taking √3 = 1.7)
Area of circle = πr2
= π × 282
= 2464 cm2
So, area of designed portion = 2464 – 1999.2 = 464.8 cm2
Cost of making design = 464.8 × 0.35
= Rs. 162.68
Question 9 :
The area of the shaded region in Fig., where arcs drawn with centres P, Q, Rand S intersect in pairs at mid-points A, B, C and D of the sides PQ, QR, RS and SP, respectively of a square PQRS, is:
(A) 25.25 cm2
(B) 27.45 cm2
(C) 29.65 cm2
(D) 30.96 cm2
Correct Answer – (D)
Question 10 :
The wheel of a motor cycle is of radius 35 cm. How many revolutions per minute must the wheel make so as to keep a speed of 66 km/h?
(A) 300
(B) 400
(C) 450
(D) 500
