CBSE Class 10 Mathematics Chapter 14 Statistics Multiple Choice Questions with Answers. MCQ Class 10 Maths Statistics with Answers was Prepared Based on Latest Exam Pattern. Students can solve NCERT Class 10 Mathematics Statistics MCQs with Answers to know their preparation level.
Multiple Choice Questions - Set - 2
Question 1:
The abscissa of the point of intersection of the less than type and of the more than type cumulative frequency curves of a grouped data gives its
(a) mean
(b) median
(c) mode
(d) all the three above
Correct Answer – (B)
Question 2 :
Choose the correct answer from the given four options : In the formula
for finding the mean of grouped data d1 s are deviation from a of
(a) lower limits of the classes
(b) upper limits of the classes
(c) mid points of the classes
(d) frequencies of the class marks
Correct Answer – (C)
Question 3 :
di is the deviation of xi from assumed mean a. If mean =
(a) class size ‘
(b) number of observations
(c) assumed mean
(d) none of these
Correct Answer – (C)
Question 4 :
For the following distribution
| Marks obtained | No. of students |
| More than or equal to 0 | 63 |
| More than or equal to 10 | 58 |
| More than or equal to 20 | 55 |
| More than or equal to 30 | 51 |
| More than or equal to 40 | 48 |
| More than or equal to 50 | 42 |
the frequency of the class 20-30 is
(a) 35
(b) 4
(c) 48
(d) 51
Correct Answer – (B)
Question 5 :
For the following distribution
| Cl | 0-5 | 5-10 | 10-15 | 15-20 | 20-25 |
| f | 10 | 15 | 12 | 20 | 9 |
the difference of the upper limit of the median class and the lower limit of the modal class is
(a) 0
(b) 5
(c) 10
(d) -5
Correct Answer – (A)
Question 6 :
While computing mean of grouped data, we assume that the frequencies are [NCERT Exemplar Problems]
(a) evenly distributed over all the classes
(b) centred at the classmarks of the classes
(c) centred at the upper limits of the classes
(d) centred at the lower limits of the classes
Correct Answer – (B)
Question 7 :
Mean of 100 items is 49. It was discovered that three items which should have been 60, 70, 80 were wrongly read as 40, 20, 50 respectively. The correct mean is
(a) 48
(b) 49
(c) 50
(d) 60
Correct Answer – (C)
Sum of 100 observations
= 100 × 49 = 4900
Correct sum
= 4900 – [40 + 20 + 50 ] + [60 + 70 + 80] = 5000
∴ Correct mean = 5000/100 = 50.
Question 8 :
The times, in seconds, taken by 150 atheletes to run a 100 m hurdle race are tabulated below:
| C.I. | f |
| 13.8-14 | 3 |
| 14 – 14.2 | 4 |
| 14.2 – 14.4 | 6 |
| 14.4 – 14.6 | 69 |
| 14.6 – 14.8 | 48 |
| 14.8-15 | 20 |
The number of atheletes who completed the race in less than 14.6 seconds is
(a) 13
(b) 69
(c) 82
(d) 130
Correct Answer – (C)
Question 9 :
For the following distribution
| Marks | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 |
| No. of students | 3 | 9 | 13 | 10 | 5 |
the number of students who got marks less than 30 is
(a) 13
(b) 25
(c) 10
(d) 12
Correct Answer – (B)
Question 10 :
In the given data:
| C.I. | f |
| 65-85 | 4 |
| 85 – 105 | 5 |
| 105 – 125 | 13 |
| 125 – 145 | 20 |
| 145 – 165 | 14 |
| 165 – 185 | 7 |
| 185 – 205 | 4 |
the difference of the upper limit of the median class and the lower limit of the modal class is
(a) 38
(b) 20
(c) 19
(d) 0
