CBSE Class 10 Mathematics Chapter 2 Polynomials Multiple Choice Questions with Answers. MCQ Questions Class 10 Mathematics Polynomials with Answers was Prepared Based on Latest Exam Pattern. Students can solve NCERT Class 10 Mathematics Polynomials MCQs with Answers to know their preparation level.
Multiple Choice Questions - Set - 6
Question 1:
When we divide x3 + 5x + 7 by x4 – 7x2 – 6 then quotient and remainder are (respectively):
(a) 0, x3 + 5x + 7
(b) x, 2x + 3
(c) 1, x4 – 7x2 – 6
(d) x2, 4x – 9
Correct Answer – (A)
Question 2 :
The value of b, for which 2x3 + 9x2 – x – b is exactly divisible by 2x + 3 is:
(a) – 15
(b) 15
(c) 9
(d) – 9
Correct Answer – (B)
Question 3 :
If α and s are two zeros of the polynomial p(x), then which of the following is a factor of p(x):
(a) (x – α)(x – s)
(b) (x + α) (x + s)
(c) k(x – α)
(d) k(x- s)
Correct Answer – (A)
Question 4 :
Find a cubic polynomial with the sum, sum of the product of its zeros taken two at a time and the product of its zeros as -2, +5, -3, respectively.
(a) 2x3 + 5x2 + x + 3
(b) 4x3 + 5x2 – 3x + 7
(c) x3 + 2x2 + 5x + 3
(d) 2x3 + 5x2 + 3x + 1
Correct Answer – (C)
Question 5 :
Write a polynomial with zeros 1, – 1 and 1.
(a) x3 + x2 + x + 1
(b) x3 – x2 + x + 1
(c) x3 – x2 – x – 1
(d) x3 – x2 – x + 1
Correct Answer – (D)
Question 6 :
The graph of a polynomial is as shown, find the polynomial
(a) k(x2 – x – 6)
(b) k(x3 + x2 + 6x)
(c) k(x3 – x2 – 6x)
(d) k(x3 – 6x)
Correct Answer – (C)
Question 7 :
If 2 ± √3 are the two zeros of a polynomial then the following is a factor:
(a) x2 – 4x + 1
(b) x2 + 4x – 1
(c) 4x2 + x – 1
(d) 4x2 – x + 1
Correct Answer – (A)
Question 8 :
If 2 is a zero of p(x) = x2 + 3x + k, find k:
(a) 10
(b) 5
(c) – 3
(d) – 10
Correct Answer – (D)
Question 9 :
Given that two of the zeroes of the polynomial, x3 + px2 + rx + s are 0, then third zero
(a) 0
(b) p/r
(c) -p/r
(d) p/q
Correct Answer – (C)
Question 10 :
Given that one of the zeroes of the polynomial ax3 + bx2 + cx + d is zero, then the product of the other two zeroes is:
(a) -c/a
(b) c/a
(c) 0
(d) -b/a
