MCQ Questions Class 11 Chemistry Some Basic Concepts of Chemistry with Answers

CBSE Class 11 Chemistry Chapter 1 Some Basic Concepts of Chemistry Multiple Choice Questions with Answers. MCQ Questions Class 11 Chemistry Some Basic Concepts of Chemistry with Answers was Prepared Based on Latest Exam Pattern. Students can solve NCERT Class 11 Chemistry Some Basic Concepts of Chemistry MCQs with Answers to know their preparation level.

Students who are searching for NCERT MCQ Questions for Class 11 Chemistry Some Basic Concepts of Chemistry with Answers are compiled here to get good practice on all fundamentals. Know your preparation level on MCQ Questions for Class 11 Chemistry with Answers. You can also verify your answers from our provided MCQ Class 11 Chemistry Some Basic Concepts of Chemistry with Answers. So, ace up your preparation with MCQ of Chapter 11 Chemistry Objective Questions.

MCQ Questions Class 11 Chemistry Some Basic Concepts of Chemistry with Answers - Set - 2

Question 1: 

The S.I unit of temperature is :
(a) Kelvin
(b) Celsius
(c) Fahrenheit
(d) Centigrade

Correct Answer – (A)

Question 2 : 

Which of the following weighs the most?
(a) One g – atom of nitrogen
(b) One mole of water
(c) One mole of sodium
(d) One molecule of H2SO4

Correct Answer – (C)

Question 3 : 

A symbol not only represents the name of the element but also represents
(a) Atomic Mass
(b) Atomic Number
(c) Atomicity
(d) Atomic Volume

Correct Answer – (C)
Explanation:
Symbol of an element represents the name along with the number of same atoms in room condition, which is its atomicity, of that element.

Question 4 : 

Which of the following contains same number of carbon atoms as are in 6.0 g of carbon (C – 12)?
(a) 6.0 g Ethane
(b) 8.0 g Methane
(c) 21.0 g Propane
(d) 28.0 g CO

Correct Answer – (B)
Explanation:
6g carbon
Moles of carbon = (6/12) = 0.5 mol
Number of carbon atoms
= 0.5 × NA =0.5NA (NA is Avogadro number)
6g ethane (C2H6 two atoms of C per mole)
Moles = (6/30) = 0.2 mol
Number of carbon atoms = 0.2 × 2 × NA = 0.4 NA
(Number of carbon atoms = moles of compound × number of C atoms per mol × Avogadro number)
8g methane (CH4)
Moles = (8/16) = 0.5 mol
Number of carbon atoms = 0.5 × 1 × NA = 0.5 NA
21g propane (C3H8)
Moles = (21/44) =0.48 mol
Number of carbon atoms = 0.48 × 3 × NA = 1.44 NA
28g CO
Moles = (28/28) =1 mol
Number of carbon atoms = 1 × 1 × NA = NA

Question 5 : 

What is the concentration of nitrate ions if equal volumes of 0.1 MAgNO3 and 0.1 M NaCl are mixed together
(a) 0.1 M
(b) 0.2 M
(c) 0.05 M
(d) 0.25 M

Correct Answer – (C)
Explanation:
0.1M AgNO3 will react with 0.1M NaCl to form 0.1M NaNO3.
But as the volume doubled, conc. of NO2
= 0.12
= 0.05 M

MCQ Questions Class 11 Chemistry Some Basic Concepts of Chemistry with Answers

Question 6 : 

The sulphate of a metal M contains 9.87% of M. This sulphate is isomorphous with ZnSO4.7H2O. The atomic weight of M is
(a) 40.3
(b) 36.3
(c) 24.3
(d) 11.3

Correct Answer – (C)
Explanation:
As the given sulphate is isomorphous with ZnSO4.7H2O its formula would be MSO4.7H2O.m is the atomic weight of M, molecular weight of MSO4.7H2O
= (m + 32 + 64 + 126) = (m + 222)
Hence % of M= [(m)/ (m+222)] × 100 = 9.87(given)
Or
100 m = (9.87 m + 222 × 9.87)
Or 90.13 m = (222 × 9.87)
Or m = (222 × 9.87)/(90.13)
= 24.3.

Question 7 : 

What is the normality of a 1 M solution of H3PO4
(a) 0.5 N
(b) 1.0 N
(c) 2.0 N
(d) 3.0 N

Correct Answer – (D)
Explanation:
H3PO4 is tribasic
So N = 3M
= 3 × 1 = 3.

Question 8 : 

The significant figures in 3400 are
(a) 2
(b) 5
(c) 6
(d) 4

Correct Answer – (B)

Question 9 : 

The number of moles present in 6 gms of carbon is:
(a) 2
(b) 0.5
(c) 5
(d) 1

Correct Answer – (B)
Explanation:
The molar mass of
12C is 12.0 gmol-1.
NA (Avogadros number = 6.022 × 1023)
12C atoms have a mass of 12.0 g.
Given that: – 6.0 g.
Thus (6.0 g)/ (12.0 gmol-1) = 0.50 mol

Question 10 : 

Which of the following cannot give iodometric titrations
(a) Fe3+
(b) Cu2+
(c) Pb2+
(d) Ag+

Correct Answer – (C)
Explanation:
Atom in highest oxidation state can oxidize iodide to liberate I2 which is volumetrically measured by iodometric titration using hypo.
2I →I2
Pb+2 → Lowest oxidation state cannot oxidise iodide to I2

MCQ Questions Class 11 Chemistry Some Basic Concepts of Chemistry with Answers

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