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MCQ Questions Class 11 Chemistry Some Basic Concepts of Chemistry with Answers - Set - 1
Question 1:
An organic compound contains carbon , hydrogen and oxygen. Its elemental analysis gave C, 38.71% and H, 9.67%. The empirical formula of the compound would be
(a) CHO
(b) CH4O
(c) CH3O
(d) CH2O
Correct Answer – (C)
Question 2 :
Which of the following weighs the most?
(a) One g – atom of nitrogen
(b) One mole of water
(c) One mole of sodium
(d) One molecule of H2SO4
Correct Answer – (C)
Question 3 :
What is the normality of a 1 M solution of H3PO4
(a) 0.5 N
(b) 1.0 N
(c) 2.0 N
(d) 3.0 N
Correct Answer – (D)
H3PO4 is tribasic
So N = 3M
= 3 × 1 = 3.
Question 4 :
The -ve charged particles is called:
(a) Anion
(b) Cation
(c) Radical
(d) Atom
Correct Answer – (A)
A charged particle, also called an ion, is an atom with a positive or negative charge.
This happens whenever something called an ionic bond forms.
Two particles that have different numbers of electrons (the smallest particle in an atom which is negative) start reacting to each other.
The particle that has the greater amount of electrons takes the other particles electrons.
One becomes positive because it lost an electron, and the other negative because it got another electron.
The two particles become attracted to each other and mix together, making a new kind of particle.
Question 5 :
The number of moles present in 6 gms of carbon is:
(a) 2
(b) 0.5
(c) 5
(d) 1
Correct Answer – (B)
Explanation:
The molar mass of
12C is 12.0 gmol-1.
NA (Avogadros number = 6.022×1023)
12C atoms have a mass of 12.0 g.
Given that: – 6.0 g.
Thus (6.0 g)/ (12.0 gmol-1) = 0.50 mol.
MCQ Questions Class 11 Chemistry Some Basic Concepts of Chemistry with Answers
Question 6 :
Under similar conditions of pressure and temperature, 40 ml of slightly moist hydrogen chloride gas is mixed with 20 ml of ammonia gas, the final volume of gas at the same temperature and pressure will be
(a) 100 ml
(b) 20 ml
(c) 40 ml
(d) 60 ml
Correct Answer – (B)
NH3(g) + HCl(g)→ NH4Cl(s)
t = 0 40ml 0
t = t 20ml solid
Final volume = 20ml.
Question 7 :
The total number of ions present in 111 g of CaCl2 is
(a) One Mole
(b) Two Mole
(c) Three Mole
(d) Four Mole
Correct Answer – (C)
Molecular weight of
CaCl2 = 111g/mol
Ions in one calcium chloride molecule = Ca+2 + 2Cl– = 3 ions
Now no. of molecules in 111g/mol of CaCl2 = Avogadros number
= 6.02 × 1023 molecules
So number of ions in 111g/mol of CaCl2
= 3 × 6.02 × 1023 ions
= 3 moles.
Question 8 :
Which is not a unit of pressure:
(a) Bar
(b) N/m²
(c) Kg/m²
(d) Torr
Correct Answer – (C)
Question 9 :
What is the concentration of nitrate ions if equal volumes of 0.1 M AgNO3 and 0.1 M NaCl are mixed together
(a) 0.1 N
(b) 0.2 M
(c) 0.05 M
(d) 0.25 M
Correct Answer – (B)
Question 10 :
Approximate atomic weight of an element is 26.89. If its equivalent weight is 8.9, the exact atomic weight of element would be
(a) 26.89
(b) 8.9
(c) 17.8
(d) 26.7
Correct Answer – (D)
Atomic weight = (Equivalent weight × Valency)
=(8.9 × 3) = 26.7
(Valency = (26.89)/(8.9) ≈ 3).
- NCERT Solutions Class 11 Chemistry Chapter 1 : Some Basic Concepts of Chemistry
- NCERT Solutions Class 11 Chemistry Chapter 2 : Structure Of The Atom
- NCERT Solutions Class 11 Chemistry Chapter 3 : Classification of Elements and Periodicity in Properties
- NCERT Solutions Class 11 Chemistry Chapter 4 : Chemical Bonding and Molecular Structure
- NCERT Solutions Class 11 Chemistry Chapter 5 : States of Matter
- NCERT Solutions Class 11 Chemistry Chapter 6 : Thermodynamics
- NCERT Solutions Class 11 Chemistry Chapter 7 : Equilibrium
- NCERT Solutions Class 11 Chemistry Chapter 8 : Redox Reactions
- NCERT Solutions Class 11 Chemistry Chapter 9 : Hydrogen
- NCERT Solutions Class 11 Chemistry Chapter 10 : The s-Block Elements
- NCERT Solutions Class 11 Chemistry Chapter 11 : The p-Block Elements
- NCERT Solutions Class 11 Chemistry Chapter 12 : Organic Chemistry: Some Basic Principles and Techniques
- NCERT Solutions Class 11 Chemistry Chapter 13 : Hydrocarbons
- NCERT Solutions Class 11 Chemistry Chapter 14 : Environmental Chemistry
