MCQ Questions Class 11 Chemistry Structure of Atom with Answers

CBSE Class 11 Chemistry Chapter 2 Structure of Atom Multiple Choice Questions with Answers. MCQ Questions Class 11 Chemistry Structure of Atom with Answers was Prepared Based on Latest Exam Pattern. Students can solve NCERT Class 11 Chemistry Structure of Atom MCQs with Answers to know their preparation level.

Students who are searching for NCERT MCQ Questions for Class 11 Chemistry Structure of Atom with Answers are compiled here to get good practice on all fundamentals. Know your preparation level on MCQ Questions for Class 11 Chemistry with Answers. You can also verify your answers from our provided MCQ Class 11 Chemistry Structure of Atom with Answers. So, ace up your preparation with MCQ of Chapter 2 Chemistry Objective Questions.

MCQ Questions Class 11 Chemistry Structure of Atom with Answers - Set - 1

Question 1: 

In the ground state, an element has 13 electrons in its M-shell. The element is_____.
(a) Copper
(b) Chromium
(c) Nickel
(d) Iron

Correct Answer – (B)
Explanation:
M shell means it is third shell ⇒ n = 3
Number of electrons in M shell = 13
⇒ 3s23p63d5
The electronic configuration is: (1s2) (2s2 2p6) (3s2 3p6 3d5) (4s1)
The element is chromium is Cr.

Question 2 : 

Which of the following element has least number of electrons in its M-shell?
(a) K
(b) Mn
(c) Ni
(d) Sc

Correct Answer – (A)
Explanation:
K = 19 = 1s²2s22p63s23p6s1
3s23p6 = m-shell
= k has only 8 electrons in M shell

Question 3 : 

The magnetic quantum number specifies
(a) Size of orbitals
(b) Shape of orbitals
(c) Orientation of orbitals
(d) Nuclear Stability

Correct Answer – (C)
The magnetic quantum number specifies orientation of orbitals

Question 4 : 

A gas absorbs a photon of 355 nm and emits at two wavelengths. If one of the emissions is at 680 nm, the other is at:
(a) 518 nm
(b) 1035 nm
(c) 325 nm
(d) 743 nm

Correct Answer – (D)
Explanation:
From Law of Conservation of energy, energy of absorbed photon must be equal to combined energy of two emitted photons.
ET = E1 + E2 ….. (1)
Where E1 is Energy of first emitted photon emitted and E2is Energy of second emitted photon.
Energy E and wavelength λ of a photon are related by the equation
E= (hc)/ (λ)….. (2)
Where Plancks constant = h, c is velocity of light.
Substituting the values from (2) in (1) we get
(hc/λT) = (hc)/ (λ1) + (hc)/ (λ2)

Question 5 : 

The ionization enthalpy of hydrogen atom is 1.312 × 106 J mol-1. The energy required to excite the electron in the atom from n = 1 to n = 2 is
(a) 8.51 × 105 J mol-1
(b) 6.56 × 105 J mol-1
(c) 7.56 × 105 J mol-1
(d) 9.84 × 105 J mol-1

Correct Answer – (D)
Explanation:
Energy required when an electron makes transition from n = 1 to n = 2
E2=−(1.312 × 106 × (1)²)/(2²)
= −3.28 × 105 J mol-1
E1 = −1.312 × 106 J mol-1
ΔE = E2 − E1
=−3.28 × 105−(−13.2 × 106)
ΔE = 9.84×105 J mol-1

MCQ Questions Class 11 Chemistry Structure of Atom with Answers

Question 6 : 

Which one of the following sets of ions represents a collection of isoelectronic species? (Atomic nos.: F = 9, Cl = 17, Na = 11, Mg = 12, Al = 13, K = 19, Ca = 20, Sc = 21)
(a) K+, Ca2+, Sc3+, Cl
(b) Na+, Ca2+ , Sc3+, F
(c) K+, Cl, Mg2+, Sc3+
(d) Na+, Mg2+, Al3+, Cl

Correct Answer – (A)
Explanation:
Isoelectronic species are those which have same number of electrons.
K+ = 19 – 1 = 18; Ca2+ = 20 – 2 = 18; Sc3+ = 21 – 3 = 18; Cl = 17 + 1 = 18
Thus all these ions have 18 electrons in them.

Question 7 : 

The electronic configuration of silver atom in ground state is
(a) [Kr]3d104s1
(b) [Xe]4f145d106s1
(c) [Kr]4d105s1
(d) [Kr]4d95s2

Correct Answer – (C)

Question 8 : 

Which of the following statements in relation to the hydrogen atom is correct?
(a) 3s orbital is lower in energy than 3p orbital
(b) 3p orbital is lower in energy than 3d orbital
(c) 3s and 3p orbitals are of lower energy than 3d orbital
(d) 3s, 3p and 3d orbitals all have the same energy

Correct Answer – (D)
Explanation:
A hydrogen atom has 1st configuration and these its, 3p and 3d orbitals will have same energy wrt 1s orbital.

Question 9 : 

For a given principal level n = 4, the energy of its subshells is in the order

(a) s < p < d < f
(b) s > p > d > f
(c) s < p < f < d
(d) f < p < d < s

Correct Answer – (A)

Question 10 : 

The increasing order (lowest first) for the values of e/m (charge/mass) for
(a) e, p, n, α
(b) n, p, e, α
(c) n, p, α, e
(d) n, α, p, e

Correct Answer – (D)

MCQ Questions Class 11 Chemistry Structure of Atom with Answers

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