CBSE Class 10 Mathematics Chapter 9 Some Applications of Trigonometry Multiple Choice Questions with Answers. MCQ Class 10 Maths Some Applications of Trigonometry with Answers was Prepared Based on Latest Exam Pattern. Students can solve NCERT Class 10 Mathematics Some Applications of Trigonometry MCQs with Answers to know their preparation level.
Multiple Choice Questions - Set - 2
Question 1:
When the length of shadow of a vertical pole is equal to √3 times of its height, the angle of elevation of the Sun’s altitude is
(a) 30°
(b) 45°
(c) 60°
(d) 15°
Correct Answer – (A)
Question 2 :
In figure given ABCD is a rectangle, the value of CE is
(a) 1 cm
(b) 2 cm
(c) 3 cm
(d) 4 cm
Correct Answer – (D)
Reason: Since ABCD is a rectangle
∴ BC = AD = 8 cm and B = 90°
In rt ∆CBE, cos 60° = AB/BC
1/2 = CE/8
CE = 4
Question 3 :
In given figure, the value of AE is
(a) 90 cm
(b) 45 cm
(c) 90√3
(d) 45√3
Correct Answer – (A)
Question 4 :
In given Fig., the angle of depression from the observing position D and E of the object at A are
(a) 60°, 60°
(b) 30°, 30°
(c) 30°, 60°
(d) 60°, 30°
Correct Answer – (C)
∴ APE, ∠2 = ∠EAB …[alt Zs]
∴ ∠2 = 60°
Hence the angles of depression at D and E are 30° and 60° respectively.
Question 5 :
In given figure, the value of CE is
(a) 12 cm
(b) 6 cm
(c) 9 cm
(d) 6√3 cm
Correct Answer – (A)
Question 6 :
In given figure, ABCD is a || gm. The lenght of AP is
(a) 2 cm
(b) 4 cm
(c) 6 cm
(d) 8 cm
Correct Answer – (C)
∴ AD = BC = 4√3
In rt ∆APD, sin 60° = APAD
⇒ √3/2=(AP/(4/√3))
⇒ 2AP = 4 × 3 = 12
∴ AP = 6 cm
Question 7 :
In given figure, AD = 4 cm, BD = 3 cm and CB = 12 cm. The value of tan θ is
(a) 5/13
(b) 12/13
(c) 5/12
(d) 12/5
Correct Answer – (C)
AB² = AD² + BD² = (4)² + (3)² = 16 + 9 = 25
∴ AB = √25 = 5
∴ In rt ∆ABC, tan θ
AB/BC = 5/12
ABBCA
Question 8 :
Some Applications Of Trigonometry Class 10 MCQ Question 5. In given figure, the length of AP is
(a) (8√3)/3 cm
(b) (80√3)/3 cm
(c) 8√3 cm
(d) 8√3 cm
Correct Answer – (B)
Question 9 :
In given figure, the value of ZC is
(a) 90°
(b) 45°
(c) 30°
(d) 60°
Correct Answer – (D)
Question 10 :
The shadow of a tower is equal to its height at 10-45 a.m. The sun’s altitude is
(a) 30°
(b) 45°
(c) 60°
(d) 90°